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If x is positive and y is 1 more than the square of x, then
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15 Apr 2018, 03:39
15 Apr 2018, 03:39
Expert Reply
00:00
Question Stats:
96% (00:41) correct
4% (05:17) wrong based on 25 sessions
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If x is positive and y is 1 more than the square of x, then what is the value of x in terms of y?
A. \(y^2 - 1\)
B. \(y^2 + 1\)
C. \(\sqrt{y}-1\)
D. \(\sqrt{y-1}\)
E. \(\sqrt{y+1}\)
A. \(y^2 - 1\)
B. \(y^2 + 1\)
C. \(\sqrt{y}-1\)
D. \(\sqrt{y-1}\)
E. \(\sqrt{y+1}\)
Drill 2
Question: 2
Page: 510
Question: 2
Page: 510
Re: If x is positive and y is 1 more than the square of x, then
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18 Apr 2018, 15:42
18 Apr 2018, 15:42
Expert Reply
Explanation
Plug in x = 4, so y = 17.
Now plug in 17 into the answers to see which gives you 4. Only choice (D) does.
Plug in x = 4, so y = 17.
Now plug in 17 into the answers to see which gives you 4. Only choice (D) does.
If x is positive and y is 1 more than the square of x, then
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Updated on: 17 Nov 2021, 16:27
Updated on: 17 Nov 2021, 16:27
1
Question states:
x is positive
It also states that "y is 1 more than the square of x"
How do you translate this statement?
We can write this as:
y = x^2 + 1
Now, we need x in terms of y?
So, what do you do?
Simple!
Rewrite equation (1) as:
x^2 = y-1
Taking square roots on both sides we get the answer as:
x = √(y-1)
x is positive
It also states that "y is 1 more than the square of x"
How do you translate this statement?
We can write this as:
y = x^2 + 1
Now, we need x in terms of y?
So, what do you do?
Simple!
Rewrite equation (1) as:
x^2 = y-1
Taking square roots on both sides we get the answer as:
x = √(y-1)
