Re: If x, y, and z are integers, and x and y are both even, which of the f
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05 Feb 2023, 09:56
OE
The product of two even numbers, such as xy, will always be even. However, z could be odd, and an even plus an odd is always odd. Therefore, the expression in choice (E) could be odd. In choices (A) and (B), an even plus an even must be even. In choice (C), an even minus an even must be even. In choice (D), yz (an even number, because y is even) plus x, which is even, will be even. Note that this problem could be easily solved by either applying these odd/even principles as demonstrated, or by picking numbers for x, y, and z.