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If x2 + x 6 < 0, what is the number of possible values of integer x
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02 Sep 2024, 07:52
02 Sep 2024, 07:52
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Question Stats:
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66% (01:22) wrong based on 12 sessions
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If \(x^2+ x – 6 < 0\), what is the number of possible values of integer x, that satisfy the given inequality?
A. 1
B. 2
C. 3
D. 4
E. 5
A. 1
B. 2
C. 3
D. 4
E. 5
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Re: If x2 + x 6 < 0, what is the number of possible values of integer x
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02 Sep 2024, 12:20
02 Sep 2024, 12:20
1
x^2 + x - 6 < 0
(x - 2) (x + 3) < 0
This means the 2 terms are of opposite signs.
Case 1
x - 2 < 0
x < 2
Case 2
x + 3 > 0
x > -3
Therefore
-3 < x < 2
Possible values
-2, -1, 0 and 1
Answer D
Adewale Fasipe, quant instructor, Lagos Nigeria.
(x - 2) (x + 3) < 0
This means the 2 terms are of opposite signs.
Case 1
x - 2 < 0
x < 2
Case 2
x + 3 > 0
x > -3
Therefore
-3 < x < 2
Possible values
-2, -1, 0 and 1
Answer D
Adewale Fasipe, quant instructor, Lagos Nigeria.
gmatclubot
Re: If x2 + x 6 < 0, what is the number of possible values of integer x [#permalink]
02 Sep 2024, 12:20
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