Re: If xy is different from zero and 2x+3y
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08 Feb 2026, 03:38
This problem can be solved by translating the verbal statement into an algebraic equation and then isolating the ratio $\frac{x}{y}$.
1. Translate the equation
The problem states: $\(2 x+3 y=175\) %$ of $8 x$. Since $175 %=1.75$ (or $\(\frac{175}{100}\)$ ), we can write:
$$
\(2 x+3 y=1.75 \times 8 x\)
$$
2. Simplify the right side
First, calculate $\(1.75 \times 8\)$ :
$$
\(1.75 \times 8=\frac{7}{4} \times 8=7 \times 2=14\)
$$
Now the equation is:
$$
\(2 x+3 y=14 x\)
$$
3. Isolate $x$ and $y$
Subtract $2 x$ from both sides to group the $x$ terms together:
$$
\(\begin{gathered}
3 y=14 x-2 x \\
3 y=12 x
\end{gathered}\)
$$
4. Find the ratio $\(\frac{x}{y}\)$
To find $\(\frac{x}{y}\)$, divide both sides by 12 and by $y$ (given $\(x y \neq 0\)$, we know $\(y \neq 0\)$ ):
$$
\(\frac{3}{12}=\frac{x}{y}\)
$$
Simplify the fraction $\(\frac{3}{12}\)$ :
$$
\(\frac{1}{4}=\frac{x}{y}\)
$$
Final Answer: The ratio $\(\frac{x}{y}\)$ is $\(1 / 4\)$, which corresponds to option $\(\mathbf{D}\)$.