arjunbir wrote:
KarunMendiratta Sir I did not get the second step?can you plese explain.
Thank you
Dear, I have used the following property;
\(\frac{x^a}{x^b} = x^{a-b}\)
\(2^{(x^2 - y^2) = \frac{2^{x^2}}{2^{y^2}}\), and
\(2^{(x^2 - 1) = \frac{2^{x^2}}{2}\)
Divide (1) and (2), to get;
\(\frac{2}{2^{y^2}}\)
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I hope this helps!
Regards:
Karun Mendiratta
Founder and Quant Trainer
Prepster Education, Delhi, Indiahttps://www.instagram.com/prepster_education/