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Re: In a certain class, every student is either a boy or a girl. [#permalink]
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Carcass wrote:
In a certain class, every student is either a boy or a girl. The boys constitute \(\frac{5}{13}\) of the students in the class.

Quantity A
Quantity B
The ratio of boys to girls in the class
The fraction of the class that are girls


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


If 5/13 of the students are boys, then the remaining 8/13 of the students are girls.
So, we might say, for every 5 boys there are, we have 8 girls.
In other words, the ratio of boys to girls = 5/8

So, we get:
QUANTITY A: 5/8
QUANTITY B: 8/13

One option is to convert these fractions to decimals (using long division or the onscreen calculator)
Here's what I'd do on test day:

Multiply both quantities by 8 to get:
QUANTITY A: 5
QUANTITY B: 64/13

Multiply both quantities by 13 to get:
QUANTITY A: 65
QUANTITY B: 64

Answer: A

Cheers,
Brent
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In a certain class, every student is either a boy or a girl. [#permalink]
I got the right approach but failed to multiply as required thank you for the explanation.
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