GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In a certain dance troupe, there are 55 women and 33 men. If all of th
[#permalink]
14 Sep 2021, 02:06
14 Sep 2021, 02:06
Expert Reply
00:00
Question Stats:
85% (01:08) correct
15% (01:34) wrong based on 20 sessions
Hide Show timer Statistics
In a certain dance troupe, there are 55 women and 33 men. If all of the women are 62 inches tall and all of the men are 70 inches tall, what is the average height of the dancers in the troupe?
(A) 60 inches
(B) 61 inches
(C) 62 inches
(D) 65 inches
(E) 63 inches
(A) 60 inches
(B) 61 inches
(C) 62 inches
(D) 65 inches
(E) 63 inches
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: In a certain dance troupe, there are 55 women and 33 men. If all of th
[#permalink]
14 Sep 2021, 06:45
14 Sep 2021, 06:45
1
1
Bookmarks
Carcass wrote:
In a certain dance troupe, there are 55 women and 33 men. If all of the women are 62 inches tall and all of the men are 70 inches tall, what is the average height of the dancers in the troupe?
(A) 60 inches
(B) 61 inches
(C) 62 inches
(D) 65 inches
(E) 63 inches
(A) 60 inches
(B) 61 inches
(C) 62 inches
(D) 65 inches
(E) 63 inches
This looks like a job for weighted averages!
Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...
55 + 33 = 88
So, there are 88 people in total.
55/88 = the proportion proportion of WOMEN in the group
And 33/88 = the proportion proportion of MEN in the group
So, the weighted average = (55/88)(62) + (33/88)(70)
= (5/8)(62) + (3/8)(70) I simplified the two fractions
= 310/8 + 210/8
= 520/8
= 260/4
= 130/2
= 65
Answer: D
RELATED VIDEO
General Discussion
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: In a certain dance troupe, there are 55 women and 33 men. If all of th
[#permalink]
14 Sep 2021, 02:35
14 Sep 2021, 02:35
1
\(8*33/88=3\)
\(3\) is added to \(62\)
average=\(65\), answer is D
explanation: \(8\) is the difference between 70 and 62
there are total 33 men who are having this difference, hence \(8*33\) spread over all 88 people is \(3\)
\(3\) is added to \(62\)
average=\(65\), answer is D
explanation: \(8\) is the difference between 70 and 62
there are total 33 men who are having this difference, hence \(8*33\) spread over all 88 people is \(3\)
Carcass wrote:
In a certain dance troupe, there are 55 women and 33 men. If all of the women are 62 inches tall and all of the men are 70 inches tall, what is the average height of the dancers in the troupe?
(A) 60 inches
(B) 61 inches
(C) 62 inches
(D) 65 inches
(E) 63 inches
(A) 60 inches
(B) 61 inches
(C) 62 inches
(D) 65 inches
(E) 63 inches
