OFFICIAL EXPLANATION


We know that in a distribution of 8500 parameters, 26.7 has $\(56^{\text {th \)$ percentile which implies $\(56 \%\)$ of $\(8500=0.56 \times 8500=4760\)$ parameters are less than 26.7

Also as 37.1 has $\(78^{\text {th \)$ percentile which means there are $\(78 \%$ of $8500=0.78 \times 8500=6630\)$ parameters less than 37.1

Note:-6630 values less than 37.1 include 26.7 which is not included in 4760

Finally the values exactly between $\(26.7 \& 37.1\)$ will be $\(6630-4760-1=1869\)$ ( 1 is subtracted as 26.7 was included in the numbers).

Hence the answer is (A).