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In a geometric series, each term is a constant multiple of
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12 Mar 2020, 04:55
12 Mar 2020, 04:55
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In a geometric series, each term is a constant multiple of the preceding one. If the first three terms in a geometric series are -2, x, and -8, which of the following could be the sixth term in the series?
(A) -32
(B) -16
(C) 16
(D) 32
(E) 64
(A) -32
(B) -16
(C) 16
(D) 32
(E) 64
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In a geometric series, each term is a constant multiple of
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12 Feb 2021, 12:20
12 Feb 2021, 12:20
In Geometric progression; ratio of 2 consecutive terms is always a constant
OR
If a, b, c are in G.P
then, \(b^2 = ac\)
Now, the given terms are: -2, x, 8
Therefore, \(x^2 = (-2)(-8)\) = 16
i.e. x = +4 or -4
The possible series could be:
-2, -4, -8, -16, -32, -64, .......
-2, +4, -8, +16, -32, +64, ......
Sixth term = +64
Hence, option E
OR
If a, b, c are in G.P
then, \(b^2 = ac\)
Now, the given terms are: -2, x, 8
Therefore, \(x^2 = (-2)(-8)\) = 16
i.e. x = +4 or -4
The possible series could be:
-2, -4, -8, -16, -32, -64, .......
-2, +4, -8, +16, -32, +64, ......
Sixth term = +64
Hence, option E
gmatclubot
In a geometric series, each term is a constant multiple of [#permalink]
12 Feb 2021, 12:20
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