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In a given river, the current is 6 mph. A certain riverboat can travel
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29 Apr 2021, 10:29
29 Apr 2021, 10:29
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In a given river, the current is 6 mph. A certain riverboat can travel 18 mph in still water. How far upstream (against the current) can the boat travel if a round trip is to take 10 hours?
A) 24
B) 48
C) 60
D) 80
E) 96
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A) 24
B) 48
C) 60
D) 80
E) 96
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Re: In a given river, the current is 6 mph. A certain riverboat can travel
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29 Apr 2021, 11:57
29 Apr 2021, 11:57
d/12 + d/24 = 10 this equation construction is correct ,right?
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Re: In a given river, the current is 6 mph. A certain riverboat can travel
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29 Apr 2021, 12:48
29 Apr 2021, 12:48
1
Carcass wrote:
In a given river, the current is 6 mph. A certain riverboat can travel 18 mph in still water. How far upstream (against the current) can the boat travel if a round trip is to take 10 hours?
A) 24
B) 48
C) 60
D) 80
E) 96
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A) 24
B) 48
C) 60
D) 80
E) 96
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Here's one approach...
Let d = distance traveled upstream
So, d = distance traveled downstream
The upstream speed = the boat speed - the current speed = 18 - 6 = 12 mph
The downstream speed = the boat speed + the current speed = 18 + 6 = 24 mph.
Let's start with a "word equation"
(time spent traveling upstream) + (time spent traveling downstream) = 10 hours
time = distance/speed
We get: d/12 + d/24 = 10
Multiply both sides by 24 to get: 2d + d = 240
Simplify: 3d = 240
Solve: d = 80
Answer: D
