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In a jar, 2/5 of the marbles are red, 1/4 are green, and 1/
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03 May 2019, 02:13
03 May 2019, 02:13
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6% (01:03) wrong based on 144 sessions
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In a jar, \(\frac{2}{5}\) of the marbles are red, \(\frac{1}{4}\) are green, and \(\frac{1}{5}\) are blue.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Number of red marbles |
Number of green and blue marbles |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: In a jar, 2/5 of the marbles are red, 1/4 are green, and 1/
[#permalink]
03 May 2019, 05:05
03 May 2019, 05:05
3
Red marbles are \(\frac{2}{5}\) of total
Green marbles are \(\frac{1}{4}\) of total and
Blue marbles are \(\frac{1}{5}\) of total.
qty A = \(\frac{2}{5}\) of x where x is the no of marbles.
qty B = (\(\frac{1}{4} + \frac{1}{5}\)) of x where x is the no of marbles.
hence qty B = \(\frac{9}{20}\) of x
\(\frac{2}{5}\)< \(\frac{9}{20}\) hence whenever x is +ve number qty B will always be greater than A and in this case no of marbles must be atleast 1 so B is greater.
Green marbles are \(\frac{1}{4}\) of total and
Blue marbles are \(\frac{1}{5}\) of total.
qty A = \(\frac{2}{5}\) of x where x is the no of marbles.
qty B = (\(\frac{1}{4} + \frac{1}{5}\)) of x where x is the no of marbles.
hence qty B = \(\frac{9}{20}\) of x
\(\frac{2}{5}\)< \(\frac{9}{20}\) hence whenever x is +ve number qty B will always be greater than A and in this case no of marbles must be atleast 1 so B is greater.
Re: In a jar, 2/5 of the marbles are red, 1/4 are green, and 1/
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13 Aug 2022, 18:08
13 Aug 2022, 18:08
1
Besides checking that 1/4 + 1/5 = 9/20 > 8/20, one could pick numbers:
40 Red
25 Green
20 Blue
40 Red < 20 + 25 Green & Blue
Answer B
40 Red
25 Green
20 Blue
40 Red < 20 + 25 Green & Blue
Answer B
