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In a regular n-sided polygon, the measure of a single angle
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26 Mar 2018, 16:05
26 Mar 2018, 16:05
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Expert Reply
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Question Stats:
85% (00:52) correct
14% (00:56) wrong based on 47 sessions
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In a regular n-sided polygon, the measure of a single angle is \(\frac{(n-2) \times 180}{n}\). The degree measure of an angle in a regular 10-sided polygon is how much greater than the degree measure of an angle in a regular 6-sided polygon?
Drill 2
Question: 5
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Question: 5
Page: 550
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Re: In a regular n-sided polygon, the measure of a single angle
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26 Mar 2018, 21:29
26 Mar 2018, 21:29
Expert Reply
This looks like a geometry problem, but it's also basically a function problem. They tell you a function (the measure of the angle) and then ask you to subtract the function with one input from the function with another input. Anyway.
Basically, just plug in 10 into the equation, and plug in 6 into the equation, and subtract the latter from the former. Let's go.
((10 - 2)x180)/10 = 8x18 = 144
((6 - 2)x180)/6 = 120
So 144 - 120 = 24. Done.
Basically, just plug in 10 into the equation, and plug in 6 into the equation, and subtract the latter from the former. Let's go.
((10 - 2)x180)/10 = 8x18 = 144
((6 - 2)x180)/6 = 120
So 144 - 120 = 24. Done.
Re: In a regular n-sided polygon, the measure of a single angle
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04 Apr 2018, 16:03
04 Apr 2018, 16:03
1
Expert Reply
Explanation
Find the measure of an angle in a regular 10-sided polygon by plugging 10 into the given formula: \(\frac{(10-2)\times 180}{10}\)=144°.
Then do the same for a regular 6-sided polygon by plugging 6 into the given formula: \(\frac{(6-2)\times 180}{6}\)=120°. Finally, 144 – 120 = 24.
Find the measure of an angle in a regular 10-sided polygon by plugging 10 into the given formula: \(\frac{(10-2)\times 180}{10}\)=144°.
Then do the same for a regular 6-sided polygon by plugging 6 into the given formula: \(\frac{(6-2)\times 180}{6}\)=120°. Finally, 144 – 120 = 24.
