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In an increasing sequence of 10 consecutive
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10 Jun 2022, 02:00
10 Jun 2022, 02:00
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In an increasing sequence of 10 consecutive integers, the sum of the first 5 integers is 560. What is the sum of the last 5 integers in the sequence?
(A) 585
(B) 580
(C) 575
(D) 570
(E) 565
(A) 585
(B) 580
(C) 575
(D) 570
(E) 565
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Joined: 10 Apr 2015
Posts: 6218
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Re: In an increasing sequence of 10 consecutive
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10 Jun 2022, 05:32
10 Jun 2022, 05:32
2
Carcass wrote:
In an increasing sequence of 10 consecutive integers, the sum of the first 5 integers is 560. What is the sum of the last 5 integers in the sequence?
(A) 585
(B) 580
(C) 575
(D) 570
(E) 565
(A) 585
(B) 580
(C) 575
(D) 570
(E) 565
Here's one approach:
Let a, b, c, d, and e be the first 5 consecutive integers, which means a + b + c + d + e = 560
Here's a unique way to list all 10 consecutive integers: a, b, c, d, e, a+5, b+5, c+5, d+5, e+5 [We can see that e is 4 greater than a, which means the number after e must be 5 greater than a, and so on]
So, the sum of the last 5 integers = (a+5) + (b+5) + (c+5) + (d+5) + (e+5)
= a + b + c + d + e + 25
= 560 + 25
= 585
Answer: A
Re: In an increasing sequence of 10 consecutive
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11 Oct 2023, 15:58
11 Oct 2023, 15:58
Hello from the GRE Prep Club BumpBot!
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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