Raj8655 wrote:
In an intercollegiate tournament, Rosebud college won 70% of the first 80 games played during the first session of the year. In order for the college to win at least 80% of the total games played during the entire year, how many more it will have to play in the remaining sessions of the year?(Note:The college wins all the games in the remaining sessions)
A)30
B)35
C)40
D)50
E)45
If we let G = the TOTAL number of games played in the ENTIRE SEASON, then ...
G - 80 = the number of games REMAINING
after the first 80 have been played
We can now start with a "word equation":
(# of wins in 1st 80 games) + (# of wins in remaining games) = (# of wins in ENTIRE season)
We get: (70% of 80) + (100% of
G - 80 = 80% of G
Rewrite as 56 + 1.0(
G - 80) = 0.8G
Expand: 56 + G - 80 = 0.8G
Simplify: -24 + G = 0.8G
Subtract G from both sides: -24 = -0.2G
Solve: G = (-24)/(-0.2)
= 24/0.2
= 240/2
= 120
So, there are 120 games in TOTAL for the year.
Since 80 games have already been played, the number of REMAINING games = 120 - 80 = 40
So, 40 games (i.e., 40 more WINS) will result in an 80% win record.
This mean 45 more WINS and 50 more WINS will result in win records that are greater than 80%
Answer: C, D and E
Cheers,
Brent