We need to find the number of ways the 6 six symbols $@,\$,\$,\$,@,\&$ be arranged on a straight line.

We know that the number of ways to arrange $$n$$ items in a straight line out of which $$p$$ are one kind identical, q are another kind identical and rest are all distinct is $$\frac{\mathrm{n}!}{\mathrm{p}!\mathrm{q}!}$$

So, using above, the number of ways to arrange 6 symbols $@, \$,\$,\$,@,\&$ out of which 3 are identical (\$ symbols) and 2 are another kind identical ($@$ symbols) is $$\frac{6!}{3!\times 2!}=\frac{6 \times 5 \times 4}{2 \times 1}=60$$

Hence the answer is (B).