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In one can of mixed nuts, 30% of the mixture is peanuts. In
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08 Jan 2018, 15:08
08 Jan 2018, 15:08
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In one can of mixed nuts, 30% of the mixture is peanuts. In another can of mixed nuts that is one-half the size of the first one, 40% is peanuts. If both cans are emptied into the same bowl, what percent of the mixed nuts in the bowl is peanuts?
A. \(16 \frac{2}{3} %\)
B. \(20 %\)
C. \(25 %\)
D. \(33 \frac{1}{3} %\)
E. \(40 %\)
Kudo for the right answer and explanation.
Re: In one can of mixed nuts, 30% of the mixture is peanuts. In
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09 Jan 2018, 00:54
09 Jan 2018, 00:54
4
lets assume:
The first can is 10 pounds then 30% of 10= 3 pounds comprises of peanuts
The second can is 1/2 of 1st can= 1/2* 10= 5 pounds of which 40% is peanuts
Hence 0.4*5 = 2 pounds comprises of peanuts
The bowl comprises of total 15 pounds of nuts of which 2+3=5 pounds is peanuts
% of peanuts in the bowl= 5/15*100= 33.33% (d)
The first can is 10 pounds then 30% of 10= 3 pounds comprises of peanuts
The second can is 1/2 of 1st can= 1/2* 10= 5 pounds of which 40% is peanuts
Hence 0.4*5 = 2 pounds comprises of peanuts
The bowl comprises of total 15 pounds of nuts of which 2+3=5 pounds is peanuts
% of peanuts in the bowl= 5/15*100= 33.33% (d)
Re: In one can of mixed nuts, 30% of the mixture is peanuts. In
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05 May 2025, 18:24
05 May 2025, 18:24
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