GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 28Live Online Class with Top GRE Expert Mike Butville
08:00 PM EDT
-10:00 PM EDT
Top scores are possible when you enroll in a powerful GRE course, taught live online + 6 months access to TTP GRE OnDemand video courses included! Class starts Mon/Wed Sept. 28, 2026 - Dec. 9, 2026, 8:00pm-10:00pm EST
In rectangle ABCD, the length is 60 percent of the width.
[#permalink]
28 Jan 2020, 10:54
28 Jan 2020, 10:54
Expert Reply
6
Bookmarks
00:00
Question Stats:
46% (01:32) correct
53% (01:23) wrong based on 52 sessions
Hide Show timer Statistics
Attachment:
#greprepclub In rectangle ABCD, the length is 60 percent of the width..jpg [ 5.84 KiB | Viewed 5283 times ]
In rectangle ABCD, the length is 60 percent of the width.
Quantity A |
Quantity B |
\(\frac{1}{10}\) area of rectangle |
The length of the rectangle |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: In rectangle ABCD, the length is 60 percent of the width.
[#permalink]
03 Feb 2020, 10:38
03 Feb 2020, 10:38
2
Plug in numbers:
case i)
L = 6 and w = 10 --> Area = 6*10 =60
1/10 *60 = 6 = length --> both equal
case ii)
L = 12 and w = 20
12*20 = 240
1/10 *240 = 24 > 12 --> A > B
therefore the relationship cannot be determined --> D
case i)
L = 6 and w = 10 --> Area = 6*10 =60
1/10 *60 = 6 = length --> both equal
case ii)
L = 12 and w = 20
12*20 = 240
1/10 *240 = 24 > 12 --> A > B
therefore the relationship cannot be determined --> D
Re: In rectangle ABCD, the length is 60 percent of the width.
[#permalink]
17 Jul 2021, 04:32
17 Jul 2021, 04:32
1
Giving that rectangle has length that is .6*width.
asking which bigger.
A) Area of Rectangle/ 10
B) Length of Rectangle ".6w".
A) (.6w^2)/10
B) .6w
multiply be 10 each we get
.6w^2 (A)
6w (b)
divide by w
(A) 0.6w, (B)6
now if w=10 the quantities are equal
however if it is 100 a is bigger then
the answer is D
asking which bigger.
A) Area of Rectangle/ 10
B) Length of Rectangle ".6w".
A) (.6w^2)/10
B) .6w
multiply be 10 each we get
.6w^2 (A)
6w (b)
divide by w
(A) 0.6w, (B)6
now if w=10 the quantities are equal
however if it is 100 a is bigger then
the answer is D
