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In the coordinate plane, points (a, b) and (c, d) are equidi : Quantitative Comparison Questions

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Re: In the coordinate plane, points (a, b) and (c, d) are equidi [#permalink]
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since both are equidistance from origin both are 5 , so ab (4,3) and cd (3,4) and and B
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Re: In the coordinate plane, points (a, b) and (c, d) are equidi [#permalink]
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ruposh6240 wrote:
since both are equidistance from origin both are 5 , so ab (4,3) and cd (3,4) and and B


But d is bigger than b..

I'm sure the answer is wrong. Let's do it another way. We should have
sqrt(b^2 + a^2) = sqrt(c^2 + d^2).
squaring both sides we get
b^2 + a^2 = c^2 + d^2
Since abs(a) > abs(c) we must have abs(b) < abs(d)
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Re: In the coordinate plane, points (a, b) and (c, d) are equidi [#permalink]
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The key to solving this problem, in my opinion (I too had struggled with it), is

Distance of line from origin is √(a^2 + b^2).

Then, everything falls into place when you look at the solutions provided.
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Re: In the coordinate plane, points (a, b) and (c, d) are equidi [#permalink]
Can't we just use the mirroring over a line (k,K) concept; where we just have to shuffle the coordinates?
This implies that the answer is B
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Re: In the coordinate plane, points (a, b) and (c, d) are equidi [#permalink]
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Re: In the coordinate plane, points (a, b) and (c, d) are equidi [#permalink]
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