Last visit was: 22 May 2024, 19:54 It is currently 22 May 2024, 19:54

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Senior Manager
Senior Manager
Joined: 20 May 2014
Posts: 285
Own Kudos [?]: 604 [0]
Given Kudos: 225
avatar
Director
Director
Joined: 03 Sep 2017
Posts: 518
Own Kudos [?]: 677 [0]
Given Kudos: 0
Send PM
avatar
Manager
Manager
Joined: 03 Dec 2017
Posts: 64
Own Kudos [?]: 23 [0]
Given Kudos: 0
Send PM
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2218 [0]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
Re: In the diagram, JL = 4 and JK = 6. [#permalink]
2
wongpcla wrote:
Bunuel can you explain this,
I am more confused after reading the other people answer,
thank you


Let me explain this,

We know in triangle with sides A,B and c

Difference of any two sides < Third side < Sum of any two sides

Now consider the triangle above,

The maximum value of the third side must be less 10, or else the triangle rule wont be applicable

Now if we consider the third side =10 (assuming maximum value)

then Area = 1/2 * base * Altitude

= 1/2 * 4 * 10 = 20

Now the minimum value of the third side must be greater than 2.

SO let us take the value of third side = 2

Then Area = 1/2 * 4 * 2 = 4.

Now the area of the triangle is either greater than 12 or less than 12

Hence the option is D. (The diagram in geometry section are not drawn to scale unless specified. Here it looks like right angle triangle but nothing is mentioned so we cannot assume.)

Let me know if you need further clarification
avatar
Manager
Manager
Joined: 03 Dec 2017
Posts: 64
Own Kudos [?]: 23 [0]
Given Kudos: 0
Send PM
Re: In the diagram, JL = 4 and JK = 6. [#permalink]
pranab01 wrote:
wongpcla wrote:
Bunuel can you explain this,
I am more confused after reading the other people answer,
thank you


Let me explain this,

We know in triangle with sides A,B and c

Difference of any two sides < Third side < Sum of any two sides

Now consider the triangle above,

The maximum value of the third side must be less 10, or else the triangle rule wont be applicable

Now if we consider the third side =10 (assuming maximum value)

then Area = 1/2 * base * Altitude

= 1/2 * 4 * 10 = 20

Now the minimum value of the third side must be greater than 2.

SO let us take the value of third side = 2

Then Area = 1/2 * 4 * 2 = 4.

Now the area of the triangle is either greater than 12 or less than 12

Hence the option is D. (The diagram in geometry section are not drawn to scale unless specified. Here it looks like right angle triangle but nothing is mentioned so we cannot assume.)

Let me know if you need further clarification


thank you very much.
now it is clear
Intern
Intern
Joined: 17 May 2019
Posts: 15
Own Kudos [?]: 12 [0]
Given Kudos: 62
Location: India
Concentration: Finance, Leadership
GPA: 3.7
WE:General Management (Health Care)
Send PM
Re: In the diagram, JL = 4 and JK = 6. [#permalink]
Begin with side rule, 4+6=10 , 6-4=2, so 3rd side will fall between 2 to 10. If 3rd side is 3 , Area will be 6, QB is Greater. if 3rd side is 9, area will be 18, now quantity A is greater, hence ans is (D)
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne