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In the equation above, if K
[#permalink]
01 Jul 2020, 10:16

Expert Reply

1

Bookmarks

Question Stats:

\(12 \sqrt{12} = k \sqrt{m}\)

In the equation above, if \(k\) and \(m\) are different integers, which of the following two answers are possible values of \(k+m\) ?

A. -27

B. -21

C. 21

D. 24

E. 27

F. 41

G. 51

In the equation above, if \(k\) and \(m\) are different integers, which of the following two answers are possible values of \(k+m\) ?

A. -27

B. -21

C. 21

D. 24

E. 27

F. 41

G. 51

Re: In the equation above, if K
[#permalink]
01 Jul 2020, 10:16

Expert Reply

Post A Detailed Correct Solution For The Above Questions And Get A Kudos.

Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!

Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!

Re: In the equation above, if K
[#permalink]
02 Jul 2020, 10:50

1

Bookmarks

How is B possible? Please explain

Re: In the equation above, if K
[#permalink]
02 Jul 2020, 11:50

1

Expert Reply

k and m are different integers

Currently, k=m, because both k and m equal to 12

\(12 \sqrt{12} = k \sqrt{m}\)

The variable m is the value under the square root symbol, rather than the value that results when m is placed under the square root symbol.

So if k and m are currently equal, but k must be different than m, how can we increase k or m ?? Factoring the square root

\(12 \times \sqrt{12} \)

\(12 \times \sqrt{4} \times \sqrt{3}\)

\(12 \times \pm 2 \times \sqrt{3}\)

\(24 \times \sqrt{3}\) or \(-24 \times \sqrt{3}\)

Now \(k = 24\) or \(k = -24\) and \(m=3\). Find \(k+m\): \(24+3=27\) or \(-24+3=-21\)

B and E are the answers

Currently, k=m, because both k and m equal to 12

\(12 \sqrt{12} = k \sqrt{m}\)

The variable m is the value under the square root symbol, rather than the value that results when m is placed under the square root symbol.

So if k and m are currently equal, but k must be different than m, how can we increase k or m ?? Factoring the square root

\(12 \times \sqrt{12} \)

\(12 \times \sqrt{4} \times \sqrt{3}\)

\(12 \times \pm 2 \times \sqrt{3}\)

\(24 \times \sqrt{3}\) or \(-24 \times \sqrt{3}\)

Now \(k = 24\) or \(k = -24\) and \(m=3\). Find \(k+m\): \(24+3=27\) or \(-24+3=-21\)

B and E are the answers

Guys, above is the official explanation. In my opinion, it is clearly bogus because the \(\sqrt{4}\) cannot be \(\pm2\) . For the GRE it is only +2 the positive root accepted.

Waiting for GreenLightTestPrep for insights

Re: In the equation above, if K
[#permalink]
02 Jul 2020, 11:59

Carcass wrote:

Guys, above is the official explanation. In my opinion, it is clearly bogus because the \(\sqrt{4}\) cannot be \(\pm2\) . For the GRE it is only +2 the positive root accepted.

Waiting for GreenLightTestPrep for insights

I concur with clearly bogus

BAD question!

_________________

Re: In the equation above, if K
[#permalink]
20 Sep 2021, 20:07

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.

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