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In the figure, ∆ABC is inscribed in the circle. The triangl
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24 Mar 2019, 00:29
24 Mar 2019, 00:29
Expert Reply
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51% (00:25) correct
48% (00:29) wrong based on 60 sessions
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#GREpracticequestion In the figure, ∆ABC is inscribed.jpg [ 25.86 KiB | Viewed 3930 times ]
In the figure, \(∆ABC\) is inscribed in the circle. The triangle does not contain the center of the circle O.
Quantity A |
Quantity B |
x |
90 |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: In the figure, ∆ABC is inscribed in the circle. The triangl
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27 Mar 2019, 09:33
27 Mar 2019, 09:33
can any post an explanation?
Re: In the figure, ∆ABC is inscribed in the circle. The triangl
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27 Mar 2019, 11:46
27 Mar 2019, 11:46
Expert Reply
An angle inscribed in a semicircle is a right angle: this is a theorem; Thales to be precise
anglessimiG.gif [ 5.29 KiB | Viewed 3812 times ]
However, when the chord DOES NOT pass through the center of the circle that 90° angle becomes obtuse, which means > 90°.
So, \(x = \angle > 90°\)
A is the answer
Attachment:
anglessimiG.gif [ 5.29 KiB | Viewed 3812 times ]
However, when the chord DOES NOT pass through the center of the circle that 90° angle becomes obtuse, which means > 90°.
So, \(x = \angle > 90°\)
A is the answer
