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In the figure, ABCD is a square, and OB is a radius of the c
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15 Oct 2018, 03:28
15 Oct 2018, 03:28
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99% (00:46) correct
0% (00:00) wrong based on 17 sessions
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#GREpracticequestion ABCD is a square, and OB is a radius of the circle.jpg [ 21.14 KiB | Viewed 3406 times ]
In the figure, ABCD is a square, and OB is a radius of the circle. If BC is a tangent to the circle and PC = 2, then what is the area of the square?
(A) 16
(B) 20
(C) 25
(D) 36
(E) 42
Re: In the figure, ABCD is a square, and OB is a radius of the c
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17 Oct 2018, 22:21
17 Oct 2018, 22:21
1
Expert Reply
Carcass wrote:
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The attachment figure.jpg is no longer available
In the figure, ABCD is a square, and OB is a radius of the circle. If BC is a tangent to the circle and PC = 2, then what is the area of the square?
(A) 16
(B) 20
(C) 25
(D) 36
(E) 42
BC is tangent to radius OB, so angle OBC is 90°
CO=PC+PO=2+3=5
Now in ∆OBC, a right angled triangle
\(OB^2+BC^2=CO^2.....BC^2=5^2-3^2=4^2....BC=4\)
So side of square is 4..
Area is 4*4=16
A
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PicsArt_10-18-10.41.40.jpg [ 13.07 KiB | Viewed 4386 times ]
gmatclubot
Re: In the figure, ABCD is a square, and OB is a radius of the c [#permalink]
17 Oct 2018, 22:21
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