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Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
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Location: India
WE:Education (Education)
In the figure above, Arc AD = Arc BC and AB is the diameter of the
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29 Aug 2021, 23:18
29 Aug 2021, 23:18
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Question Stats:
94% (01:41) correct
5% (01:49) wrong based on 17 sessions
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Measure of Angle x.png [ 5.33 KiB | Viewed 2268 times ]
In the figure above, Arc AD = Arc BC and AB is the diameter of the circle.
Quantity A |
Quantity B |
x° |
20° |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
In the figure above, Arc AD = Arc BC and AB is the diameter of the
[#permalink]
31 Aug 2021, 21:18
31 Aug 2021, 21:18
Explanation:
Let Arc AD = Arc BC = \(y°\)
We know, AB is the diameter of circle O
So, Arc AD + Arc DC + Arc BC = \(180°\)
i.e. \(y° + 50° + y° = 180°\)
\(y = 65°\)
Thus, \(∠AOD = ∠BOC = 65°\)
Applying the property of Central Angle;
\(∠CAB = \frac{∠BOC}{2} = \frac{65°}{2} = 32.5°\)
Col. A: \(32.5°\)
Col. B: \(20°\)
Hence, option A
Let Arc AD = Arc BC = \(y°\)
We know, AB is the diameter of circle O
So, Arc AD + Arc DC + Arc BC = \(180°\)
i.e. \(y° + 50° + y° = 180°\)
\(y = 65°\)
Thus, \(∠AOD = ∠BOC = 65°\)
Applying the property of Central Angle;
\(∠CAB = \frac{∠BOC}{2} = \frac{65°}{2} = 32.5°\)
Col. A: \(32.5°\)
Col. B: \(20°\)
Hence, option A
Attachments
Measure of Angle x.png [ 7.78 KiB | Viewed 2000 times ]
General Discussion
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
In the figure above, Arc AD = Arc BC and AB is the diameter of the
[#permalink]
30 Aug 2021, 17:25
30 Aug 2021, 17:25
x=65 and answer is A
