Explanation:

Let Arc AD = Arc BC = \(y°\)

We know, AB is the diameter of circle O
So, Arc AD + Arc DC + Arc BC = \(180°\)
i.e. \(y° + 50° + y° = 180°\)
\(y = 65°\)

Thus, \(∠AOD = ∠BOC = 65°\)

Applying the property of Central Angle;
\(∠CAB = \frac{∠BOC}{2} = \frac{65°}{2} = 32.5°\)

Col. A: \(32.5°\)
Col. B: \(20°\)

Hence, option A

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x=65 and answer is A

how is the value of x=65 ?

It is not!
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Is the answer C?. ABD is a 90 triangle with angles 50+x,x and 90

Does anyone have solution to this problem?

Solution please!