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Re: In the figure above. quadrilateral ABCD is inscribed in a ci [#permalink]
I thought it was a trick. We do know 2 angles, ABC and ADC are both 90.
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In the figure above. quadrilateral ABCD is inscribed in a ci [#permalink]
I dont know why the answer is D, but if we draw a line from B to CENTER O, then one equilateral and one isosceles triangle is formed. Similar drawing can be done in lower part too. I am getting more than 12 in quantity A. rx10 GreenlightTestPrep rx10 KarunMendiratta sir, can you please confirm?
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Re: In the figure above. quadrilateral ABCD is inscribed in a ci [#permalink]
1
The radius is not given.
How can you make an equilateral triangle? isosceles I can understand with both side as radius but equilateral how?

We are not given any measure of angles as well as length hence we can't conclude anything. So D


kumarneupane4344 wrote:
I dont know why the answer is D, but if we draw a line from B to CENTER O, then one equilateral and one isosceles triangle is formed. Similar drawing can be done in lower part too. I am getting more than 12 in quantity A. rx10 GreenlightTestPrep rx10 @karunmendiretta sir, can you please confirm?
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Re: In the figure above. quadrilateral ABCD is inscribed in a ci [#permalink]
rx10 wrote:
The radius is not given.
How can you make an equilateral triangle? isosceles I can understand with both side as radius but equilateral how?

We are not given any measure of angles as well as length hence we can't conclude anything. So D


kumarneupane4344 wrote:
I dont know why the answer is D, but if we draw a line from B to CENTER O, then one equilateral and one isosceles triangle is formed. Similar drawing can be done in lower part too. I am getting more than 12 in quantity A. rx10 GreenlightTestPrep rx10 @karunmendiretta sir, can you please confirm?



Ohh I see. My bad. Now I understood sir.
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Re: In the figure above. quadrilateral ABCD is inscribed in a ci [#permalink]
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