Re: In the figure above, the area of the shaded square region is
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03 Jan 2021, 02:57
Let us consider the side of the big square as a
The area of the big square would then be \(a^2\)
Any diagonal cuts through the square in equal halves. With 2 diagonals the square is split in 4 equal sizes.
The area of the big triangle consisting the shaded square is \(\frac{1}{4} \) \(a^2\)
If you take any diagonal of the shaded square its length would be \(\frac{1}{2}\) a
The shaded square can be divided into two equal triangle of 45-45-90
The length of such a triangle is \(x:x:x\sqrt{2}\)
Therefore, \(x\sqrt{2}\) = \(\frac{1}{2}\) a
From this we can calculate a side of the shaded square as \(1/2\sqrt{2}\)*\(a\)
Area of the shaded square would be \(\frac{1}{2}\sqrt{2} * a \)* \(1/2\sqrt{2} * a\) = \(\frac{1}{8}\) * \(a^2
\)
Hence, this enables us to calculate the percentage as:
\(\frac{1}{8}\) \(a^2\) / \(a^2\) * 100
\(a^2\) cancels out giving \(\frac{100}{8}\) = 12.5 %