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Re: In the figure above the square
[#permalink]
08 Jun 2021, 09:32
Carcass wrote:
In the figure above the square has two sides which are tangent to the circle. If the area of the circle is 4a²π, what is the area of the square?
A. 2a² B. 4a C. 4a² D. 16a² E. 64a²
The area of the circle is 4a²π Area of circle = π(radius)² = 4a²π = π4a² = π(2a)² So, the radius = 2a This means the diameter = 4a (diameter is TWICE the radius)
What is the area of the square? Each side of the square has length 4a Area of square = side² = (4a )² = 16a² = D