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In the figure below, ABCD is a rectangle, and BE and CF are
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01 Feb 2019, 11:41
01 Feb 2019, 11:41
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In the figure below, ABCD is a rectangle, and BE and CF are arcs of circles centered at A and D. What is the area of the striped region?
#GREpracticequestion In the figure below, ABCD.jpg [ 16.32 KiB | Viewed 5352 times ]
A) \(10 - \pi\)
B) \(2 (5 - \pi)\)
C) \(2 (5 - 2\pi)\)
D) \(6 + 2\pi\)
E) \(5 (2 - \pi)\)
Attachment:
#GREpracticequestion In the figure below, ABCD.jpg [ 16.32 KiB | Viewed 5352 times ]
A) \(10 - \pi\)
B) \(2 (5 - \pi)\)
C) \(2 (5 - 2\pi)\)
D) \(6 + 2\pi\)
E) \(5 (2 - \pi)\)
Re: In the figure below, ABCD is a rectangle, and BE and CF are
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02 Feb 2019, 06:39
02 Feb 2019, 06:39
3
Carcass wrote:
In the figure below, ABCD is a rectangle, and BE and CF are arcs of circles centered at A and D. What is the area of the striped region?
A) \(10 - \pi\)
B) \(2 (5 - \pi)\)
C) \(2 (5 - 2\pi)\)
D) \(6 + 2\pi\)
E) \(5 (2 - \pi)\)
Attachment:
#GREpracticequestion In the figure below, ABCD.jpg
A) \(10 - \pi\)
B) \(2 (5 - \pi)\)
C) \(2 (5 - 2\pi)\)
D) \(6 + 2\pi\)
E) \(5 (2 - \pi)\)
Explanation::
The area of the rectangle = 5 * 2 = 10
Now for the arc area;
\(\frac{{Arc Area}}{{Circle Area}} = \frac{90}{360}\)
or Arc area =\(\frac{90}{360} * \pi * {radius}^2\)( radius of the circle = 2)
or Arc area = \(\pi\)
Since there are 2 Arc and both have the same radius ,
Therefore the area covered by the 2 Arc = \(2\pi\)
Therefore the Area of the shaded region = \(10 - 2\pi = 2(5 - \pi)\)
Re: In the figure below, ABCD is a rectangle, and BE and CF are
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07 Jun 2021, 02:43
07 Jun 2021, 02:43
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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