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In the figure, line segments RM, SM, and TM bisect the angle
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05 Dec 2019, 12:02
05 Dec 2019, 12:02
Expert Reply
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Question Stats:
58% (01:11) correct
41% (01:49) wrong based on 53 sessions
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Attachment:
#greprepclub In the figure, line segments.jpg [ 26.03 KiB | Viewed 6403 times ]
In the figure, line segments \(RM\), \(SM\), and \(TM\) bisect the angles of \(\triangle RST\).
Quantity A |
Quantity B |
\(\frac{x+y}{2}\) |
\(33\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: In the figure, line segments RM, SM, and TM bisect the angle
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15 Jan 2020, 07:15
15 Jan 2020, 07:15
1
Carcass wrote:
Attachment:
#greprepclub In the figure, line segments.jpg
In the figure, line segments \(RM\), \(SM\), and \(TM\) bisect the angles of \(\triangle RST\).
Quantity A |
Quantity B |
\(\frac{x+y}{2}\) |
\(33\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
line segments \(RM\), \(SM\), and \(TM\) bisect the angles of \(\triangle RST\)
so,
\(\angle MSR = \angle MST = y\)
\(\angle SRM = \angle TRM = x\)
\(\angle MTR = \angle MTS = 24\)
In \(\triangle RST\),
\(\angle MSR + \angle MST + \angle SRM + \angle TRM + \angle MTR + \angle MTS = 180\)
or \(2y + 2x + 48 =180\)
or\( x + y = 66\)
Now,
QTY A = \(\frac{x+y}{2}\) = \(\frac{66}{2} = 33\)
QTY B = \(33\)
i.e Option C
gmatclubot
Re: In the figure, line segments RM, SM, and TM bisect the angle [#permalink]
15 Jan 2020, 07:15
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