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In the figure shown, ABCDEF is a regular hexagon and AOF is
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21 Mar 2019, 12:01
21 Mar 2019, 12:01
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Question Stats:
93% (00:35) correct
6% (00:59) wrong based on 16 sessions
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#GREpracticequestion In the figure shown, ABCDEF is.jpg [ 18.83 KiB | Viewed 4143 times ]
In the figure shown, ABCDEF is a regular hexagon and AOF is an equilateral triangle. The perimeter of \(∆AOF\) is 2a feet. What is the perimeter of the hexagon in feet?
(A) 2a
(B) 3a
(C) 4a
(D) 6a
(E) 12a
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Re: In the figure shown, ABCDEF is a regular hexagon and AOF is
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04 Apr 2019, 17:29
04 Apr 2019, 17:29
1
Expert Reply
Carcass wrote:
Attachment:
#GREpracticequestion In the figure shown, ABCDEF is.jpg
In the figure shown, ABCDEF is a regular hexagon and AOF is an equilateral triangle. The perimeter of \(∆AOF\) is 2a feet. What is the perimeter of the hexagon in feet?
(A) 2a
(B) 3a
(C) 4a
(D) 6a
(E) 12a
We see that each side of the triangle = each side of the hexagon = 2a/3, so the perimeter of the hexagon is 2a/3 x 6 = 4a.
Answer: C
gmatclubot
Re: In the figure shown, ABCDEF is a regular hexagon and AOF is [#permalink]
04 Apr 2019, 17:29
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