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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
In the figure shown, line segments QS and RT are diameters of the circ
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10 Jan 2023, 01:29
10 Jan 2023, 01:29
Expert Reply
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Question Stats:
50% (00:57) correct
50% (01:24) wrong based on 4 sessions
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In the figure shown, line segments QS and RT are diameters of the circle. If the distance between Q and R is \(\frac{8}{\sqrt{2}}\), what is the area of the circle?
(A) \(4 \pi\)
(B) \(8 \pi\)
(C) \(16 \pi\)
(D) \(32 \pi\)
(E) \(64 \pi\)
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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: In the figure shown, line segments QS and RT are diameters of the circ
[#permalink]
12 Jan 2023, 21:55
12 Jan 2023, 21:55
1
Expert Reply
Let the center of the circle be O. Then OQ and OR will be the radii. Now as triangle OQR is a right angle then QR will be its hypotenuse hence \(QR^2=(\frac{8}{\sqrt{2}})^2=r^2+r^2\) --> \(2r^2=32\) --> \(r^2=16\) --> \(area=\pi{r^2}=16\pi\).
Answer: C
Answer: C
gmatclubot
Re: In the figure shown, line segments QS and RT are diameters of the circ [#permalink]
12 Jan 2023, 21:55
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