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Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
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Carcass wrote:
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

Quantity A
Quantity B
The least possible value of x
zero



A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation



Here the distance between the centre of the circle (3,2) to the point (3,0),tangent to x asis is = \(\sqrt{(3-3)^2 + (0-2)^2}\) = 2, which is the radius of the circle.

Now (x,y) is any point in this circle with radius 2, so the minimum value of x > 0

Hence option A
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Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
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the least possible value of x is 1 as the radius is 2. So while touching (1,2 ) point , x will be the least possible value
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Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
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Carcass wrote:
In the rectangular coordinate system, (x,y) is a point on a circle that has center (3,2) and is tangent to the x-axis at (3,0).

Quantity A
Quantity B
The least possible value of x
zero



A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal
D. The relationship cannot be determined from the information given.

kudo for the right solution and explanation



Now the distance between points (3,2) and (3,0) will be the radius, so radius = 2, which is the change in y axis when x remains 3.

We are looking for the least possible value of x will be the distance between center and radius 2. Thus 3-2=1
But B is 0.

Hence A is greater.

A
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Re: In the rectangular coordinate system, (x,y) is a point on a [#permalink]
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