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In the trapezoid above, AE = ED = 3 and BC is parallel to AD
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17 Sep 2018, 16:51
17 Sep 2018, 16:51
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In the trapezoid above, AE = ED = 3 and BC is parallel to AD.
Quantity A |
Quantity B |
The area of the trapezoid |
\(35\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: In the trapezoid above, AE = ED = 3 and BC is parallel to AD
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28 Nov 2018, 08:23
28 Nov 2018, 08:23
2
1
area of a trapezoid = \(\frac{sum of parallel sides * height}{2}\)
One of the parallel sides AD is divided into sides of 3 each so this side =6
and we can get the height as it is one side of the Pythagoras triplet 3-4-5 so height = 4
area = \(\frac{(6+7)*4}{2}\)
area = 26
One of the parallel sides AD is divided into sides of 3 each so this side =6
and we can get the height as it is one side of the Pythagoras triplet 3-4-5 so height = 4
area = \(\frac{(6+7)*4}{2}\)
area = 26
Re: In the trapezoid above, AE = ED = 3 and BC is parallel to AD
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30 Sep 2021, 01:26
30 Sep 2021, 01:26
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