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In the triangle shown above, BD is parallel to EC. If AC = 15, BC =
[#permalink]
09 Jan 2025, 01:33
09 Jan 2025, 01:33
Expert Reply
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Question Stats:
66% (01:59) correct
33% (04:40) wrong based on 3 sessions
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GRe triangle.png [ 29.06 KiB | Viewed 243 times ]
In the triangle shown above, BD is parallel to EC. If AC = 15, BC = 5 and AD = 5, what is the length of ED?
A. 1.5
B. 2.5
C. 3.5
D. 4.5
E. 5
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In the triangle shown above, BD is parallel to EC. If AC = 15, BC =
[#permalink]
18 Feb 2025, 03:53
18 Feb 2025, 03:53
Expert Reply
OFFICIAL EXPLANATION
As $\(B D\)$ is parallel to $\(E C, \triangle \mathrm{ABD} \sim \triangle \mathrm{ACE}\)$
Let the length of DE be ' $\(x\)$ '
In similar triangles, the ratio of the corresponding sides is same, so for triangle $\(A B D\)$ \& triangle ACE , we get $\(\frac{AD}{AE}=\frac{AB}{AC}\)$ i.e. $\(\frac{5}{5+X}=\frac{15-5}{15}=\frac{10}{15} \Rightarrow \mathrm{x}=2.5\)$
Hence the answer is (B).
As $\(B D\)$ is parallel to $\(E C, \triangle \mathrm{ABD} \sim \triangle \mathrm{ACE}\)$
Let the length of DE be ' $\(x\)$ '
In similar triangles, the ratio of the corresponding sides is same, so for triangle $\(A B D\)$ \& triangle ACE , we get $\(\frac{AD}{AE}=\frac{AB}{AC}\)$ i.e. $\(\frac{5}{5+X}=\frac{15-5}{15}=\frac{10}{15} \Rightarrow \mathrm{x}=2.5\)$
Hence the answer is (B).
gmatclubot
In the triangle shown above, BD is parallel to EC. If AC = 15, BC = [#permalink]
18 Feb 2025, 03:53
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