Re: In the triangle shown, x and y are measures of the angles A and C, re
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20 Aug 2025, 08:56
In the triangle above, we know that $\(x+y>90^{\circ}\)$; we need to compare the length of $A B$ with the length of BC .
Since the values of angle $A C B$ \& angle $B C A$ i.e. the values of $y$ and $x$ are not known, we cannot compare the lengths of the sides opposite to them.
For example if we take $\(x=y=50^{\circ}\)$, we have $\(x+y>90^{\circ}\)$ and we get the sides $A B=A C$ (in a triangle when two angles are equal, opposite sides are also equal), so column $A$ gets same quantity as column B.
But if take $\(\mathrm{x}=70^{\circ}\)$ and $\mathrm{y}=50^{\circ}$ say, we get $\(\mathrm{x}+\mathrm{y}>90^{\circ}\)$ and $\(\mathrm{AB}<\mathrm{AC}\)$ (In a triangle, side opposite to larger angle is longer), so column $B$ gets higher quantity than column $A$.
Hence a unique comparison cannot be formed between column A and column B quantities, so the answer is (D).