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In the xy-coordinate plane shown above,
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20 Feb 2021, 05:51
20 Feb 2021, 05:51
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86% (00:53) correct
13% (01:02) wrong based on 53 sessions
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In the xy-coordinate plane shown above, line \(\ell\) passes through the origin, point \(P\) lies on line \( \ell\), and the (x, y) coordinates of point P are (2, 1).
Quantity A |
Quantity B |
The slope of line 1 |
The slope of any line perpendicular to line 1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
In the xy-coordinate plane shown above,
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20 Feb 2021, 06:13
20 Feb 2021, 06:13
2
Solution:
Slope of line l =\(\frac{y2-y1}{x2-x1}\)=\(\frac{1-0}{2-0}\)=\(\frac{1}{2}\)
A Slope perpendicular to line l will be negative reciprocal of line l =-2
Thus \(\frac{1}{2}\)>-2
Qty A>Qty B
IMO A
Hope this helps!
Slope of line l =\(\frac{y2-y1}{x2-x1}\)=\(\frac{1-0}{2-0}\)=\(\frac{1}{2}\)
A Slope perpendicular to line l will be negative reciprocal of line l =-2
Thus \(\frac{1}{2}\)>-2
Qty A>Qty B
IMO A
Hope this helps!
General Discussion
In the xy-coordinate plane shown above,
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Updated on: 27 Apr 2021, 03:19
Updated on: 27 Apr 2021, 03:19
3
Ks1859 wrote:
Solution:
Slope of line l =\(\frac{y2-y1}{x2-x1}\)=\(\frac{1-0}{2-0}\)=\(\frac{1}{2}\)
A Slope perpendicular to line l will be negative reciprocal of line l =-2
Thus \(\frac{1}{2}\)>-2
Qty A>Qty B
IMO A
Hope this helps!
Slope of line l =\(\frac{y2-y1}{x2-x1}\)=\(\frac{1-0}{2-0}\)=\(\frac{1}{2}\)
A Slope perpendicular to line l will be negative reciprocal of line l =-2
Thus \(\frac{1}{2}\)>-2
Qty A>Qty B
IMO A
Hope this helps!
Nice.
Conceptually, since the slope of line l is positive, we don't necessarily need to know the value. Just need to know that any perpendicular line will have a negative slope. Since a negative is always less than positive, A is correct.
