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In the xy-coordinate system, the distance between the point (0,0) and

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In the xy-coordinate system, the distance between the point (0,0) and [#permalink] New post   12 Oct 2022, 06:05
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In the xy-coordinate system, the distance between the point (0,0) and point P is \(\sqrt{40}\) . Which of the following could be the coordinates of point P?

(A) (4,7)
(B) (4,10)
(C) (5,6)
(D) (6,2)
(E) (20,20)



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D
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Re: In the xy-coordinate system, the distance between the point (0,0) and [#permalink] New post   17 Oct 2022, 00:53
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Let the coordinates of P be (x,y)

now distance between (0,0) and (x,y) =
the square root of 40 = square root of (x^2+y^2)

Square root from both sides gets canceled. now we can check with the options given and whichever option gives us x^2+y^2 = 40 will be the answer.

Answer D
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Re: In the xy-coordinate system, the distance between the point (0,0) and [#permalink] New post   03 Jul 2024, 01:01
Hello from the GRE Prep Club BumpBot!

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Re: In the xy-coordinate system, the distance between the point (0,0) and [#permalink]
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