GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In trapezium ABCD, AB||CD and AC = BD. If area of the
[#permalink]
30 Jul 2019, 05:00
30 Jul 2019, 05:00
2
1
Bookmarks
00:00
Question Stats:
33% (01:35) correct
66% (01:50) wrong based on 6 sessions
Hide Show timer Statistics
In trapezium ABCD, AB||CD and AC = BD. If area of the trapezium is 60 sq units and height of the trapezium is 10 units, what is the length of diagonal BD?
A) 10 units
B)\(\sqrt{116}\) units
C) 5\(\sqrt{5}\) units
D) \(\sqrt{136}\)
E) 12 units
Source: Jamboree Green Book 1
A) 10 units
B)\(\sqrt{116}\) units
C) 5\(\sqrt{5}\) units
D) \(\sqrt{136}\)
E) 12 units
Source: Jamboree Green Book 1
Re: In trapezium ABCD, AB||CD and AC = BD. If area of the
[#permalink]
10 Aug 2019, 22:51
10 Aug 2019, 22:51
2
Area = 60
0.5(AB + CD)(10) = 60
AB + CD = 12
From the below figure, we have
CD = EF = x
AB = 12 - x
AE = FB = (12-2x)/2 = 6 - x (Since AC = BD, the two triangles are similar)
EB = 6 - x + x = 6
BE = 10
Triangle DEB is right angled --> BD^2 = 100 + 36 = 136
BD = sqrt(136)
Answer: D
0.5(AB + CD)(10) = 60
AB + CD = 12
From the below figure, we have
CD = EF = x
AB = 12 - x
AE = FB = (12-2x)/2 = 6 - x (Since AC = BD, the two triangles are similar)
EB = 6 - x + x = 6
BE = 10
Triangle DEB is right angled --> BD^2 = 100 + 36 = 136
BD = sqrt(136)
Answer: D
Attachments
Trapezium.png [ 12.29 KiB | Viewed 3726 times ]
Re: In trapezium ABCD, AB||CD and AC = BD. If area of the
[#permalink]
11 Aug 2019, 05:49
11 Aug 2019, 05:49
Vyshak wrote:
Area = 60
0.5(AB + CD)(10) = 60
AB + CD = 12
From the below figure, we have
CD = EF = x
AB = 12 - x
AE = FB = (12-2x)/2 = 6 - x (Since AC = BD, the two triangles are similar)
EB = 6 - x + x = 6
BE = 10
Triangle DEB is right angled --> BD^2 = 100 + 36 = 136
BD = sqrt(136)
Answer: D
0.5(AB + CD)(10) = 60
AB + CD = 12
From the below figure, we have
CD = EF = x
AB = 12 - x
AE = FB = (12-2x)/2 = 6 - x (Since AC = BD, the two triangles are similar)
EB = 6 - x + x = 6
BE = 10
Triangle DEB is right angled --> BD^2 = 100 + 36 = 136
BD = sqrt(136)
Answer: D
Could u elaborate from :
AE = FB = (12-2x)/2 = 6 - x (Since AC = BD, the two triangles are similar)
EB = 6 - x + x = 6
BE = 10
