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Re: In triangle FGH, the base has a length of FH = 126.3, and th [#permalink]
The trick is to multiply 126.3 with such number which makes it integer and also check if it is divisible by 2.
So, if you multiply 126.3 * 40 and 126.3 * 80 and 126.3*100 it will give you value in integer and the number will be divided by 2 also.
Hence B,E,F is the answer
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Re: In triangle FGH, the base has a length of FH = 126.3, and th [#permalink]
Write 126.3 as 126+(3/10)

The area of the triangle will be
=(1/2)(126+ (3/10))*h
=(1/2)(126*h)+(1/2)(3/10)*h

This value will be an integer when h is an integer, it is divisible by 10 and by 4.
Why 4? B/c once we divide it by 10 it will lose a factor of 2, and we will need another one when it is multiplied by (1/2)


40,80, and 100 are the only ones satisfying these requirements.

Final Answer: B, E, F
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Re: In triangle FGH, the base has a length of FH = 126.3, and th [#permalink]
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