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is a prime number, xy is even, and x > 4y > 0.

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sandy
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is a prime number, xy is even, and x > 4y > 0. [#permalink] New post   02 Sep 2018, 07:14
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\(\sqrt{xy}\) is a prime number, xy is even, and x > 4y > 0.

Quantity A
Quantity B
\(y\)
\(1\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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B
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indiragre18
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Re: is a prime number, xy is even, and x > 4y > 0. [#permalink] New post   21 Nov 2018, 11:24
Shouldn't the answer be B?
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chetan2u
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Re: is a prime number, xy is even, and x > 4y > 0. [#permalink] New post   21 Nov 2018, 20:28
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indiragre18 wrote:
Shouldn't the answer be B?

sandy wrote:
\(\sqrt{xy}\) is a prime number, xy is even, and x > 4y > 0.

Quantity A
Quantity B
\(y\)
\(1\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



Hi..
√(xy) is prime and xy is even...
So √(xy) has to be 2..
Thus xy=4...X=4/y
Now we are told X>4y>0
So 4/y>4y.....\(y^2<1.....y<1\)

So yes 1>y means B>A

Hence answer should be B
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Salsanousi
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Re: is a prime number, xy is even, and x > 4y > 0. [#permalink] New post   23 Nov 2018, 09:48
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sandy wrote:
\(\sqrt{xy}\) is a prime number, xy is even, and x > 4y > 0.

Quantity A
Quantity B
\(y\)
\(1\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



The only even prime is 2 so xy must be 4 and hence square root of (xy) it has to be 2.

Meaning xy = 4
x = 4/y

4/y > 4y > 0

Divide by 4 and multiplty by y

1 > y^2 > 0

That means y is less than one.

Hence the correct answer choice should B
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is a prime number, xy is even, and x > 4y > 0. [#permalink] New post   26 May 2022, 22:20
Hi,
Can anyone please help me understand the following:
I understood the part about how y is less than 1 following the reasoning given. But if it were asked what are the possible values of x and y, what would those be?
We know (x)(y) = 4 and y is a fraction less than 1 but greater than 0. Given that x can be any number (integer or fraction) greater than 0, so the possible values for x and corresponding y to yield xy = 4 is infinite, right?

Please correct me if I am wrong.
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is a prime number, xy is even, and x > 4y > 0. [#permalink] New post   27 May 2022, 08:10
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Yeah, right.

As long as \(xy = 4\), there will be many values (integers, fractions). Hence, to remove obscurity, some conditions will be mentioned.
17221058 wrote:
Hi,
Can anyone please help me understand the following:
I understood the part about how y is less than 1 following the reasoning given. But if it were asked what are the possible values of x and y, what would those be?
We know (x)(y) = 4 and y is a fraction less than 1 but greater than 0. Given that x can be any number (integer or fraction) greater than 0, so the possible values for x and corresponding y to yield xy = 4 is infinite, right?

Please correct me if I am wrong.
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is a prime number, xy is even, and x > 4y > 0. [#permalink]
27 May 2022, 08:10
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