wongpcla wrote:
simon1994 wrote:
Here we can set up the following equation with both Areas:
1) Triangle: (a^2)/2 = A
2) Sqaure: b^2 = A
A stands for Area, a for side of triangle and b for side of square.
If we solve these equations for the sides a and b respectively, we obtain the following
1) a^2 = 2A
2) b^2 = A
Now we can set up perimeter equations with the comparable variable A
1) 2A * 3 => 6A
2) A*4 => 4A
Hence the perimeter of the triangle(6A) is bigger than that of the square(4A) Therefore A>B
Would you explain why you put "2A * 3" and "A*4"
you times their area, this is also okay to compare their sides?
thank you !
Hi,
I changed by previous answer their was a slight mistake. However the reasoning remains the same.
Regarding your question: We need to obtain compare the Perimeter of a triangle with the perimeter of a square.
So we we have to multiply by 3 to obtain the perimeter of a triangle and by 4 to obtain the perimeter of a square.
Hope that helped!