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J is the set of all fractions in the form of
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25 Jan 2020, 06:51
25 Jan 2020, 06:51
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Question Stats:
69% (00:36) correct
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J is the set of all fractions in the form of \(\frac{a}{a^2}\) when \(a \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
Any member of set J |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
GRE Instructor
Joined: 19 Jan 2020
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Posts: 117
Given Kudos: 0
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Re: J is the set of all fractions in the form of
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26 Jan 2020, 07:41
26 Jan 2020, 07:41
1
Carcass wrote:
J is the set of all fractions in the form of \(\frac{a}{a^2}\) when \(a \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
Any member of set J |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
We have the fraction \(\frac{a}{a^2} = \frac{1}{a}\)
If \(a\) is a fraction between 0 and 1, say 1/2: \(\frac{1}{a}\) = 2 => Quantity A is greater than Quantity B
If \(a\) = 1: \(\frac{1}{a}\) = 1 => Quantity A is equal to Quantity B
If \(a\) is a number greater than 1, say 2: \(\frac{1}{a}\) = 1/2 => Quantity A is less than Quantity B
Thus, there is no relation between the two quantities
Answer D
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: J is the set of all fractions in the form of
[#permalink]
26 Jan 2020, 09:09
26 Jan 2020, 09:09
1
Carcass wrote:
J is the set of all fractions in the form of \(\frac{a}{a^2}\) when \(a \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
Any member of set J |
1 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
If \(a = 1\), then Quantity A = Quantity B
If \(a = 2\), then Quantity A < Quantity B
Answer: D
Cheers,
Brent
