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Re: Jack is storing a rectangular box inside a cylindrical conta [#permalink]
here, h=20, r=7=> d=14

as the height of the cylinder is 20 inches, we can fit a rectangular box having a height atmost= 20 inches

the maximum length and/or width of the rectangular box can be, x= 7* sqrt(2)=9.87 (approx)

[d^2= x^2+x^2=>x=7*sqrt(2)]

therefore, the box will be such that it's length, l<=9.87; width, W<=9.87 and height, H<=20

only A, B, D and F fulfil the above conditions.
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Re: Jack is storing a rectangular box inside a cylindrical conta [#permalink]
3
The cylinder has height =20, diameter, d=14 [πr2h=980π ⟹ r =7]

So, the rectangle height must be ≤ 20
And the face diagonal of another two side must be less than or equal diameter
√ (w^2+L^2) ≤ 14
0r w^2+L^2≤196

A. 3^2+6^2=45

B. 6^2 +9^2=117

C. 10^2 +10^2=200

D. 8^2 +9^2=145

E. 11^2 +15^2=346

F. 92 +92=162


Answer: ABDF
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Re: Jack is storing a rectangular box inside a cylindrical conta [#permalink]
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Re: Jack is storing a rectangular box inside a cylindrical conta [#permalink]
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