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Jill is dividing her ten-person class into two teams
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08 Jun 2019, 05:53
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100% (00:42) wrong based on 3 sessions
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Jill is dividing her ten-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?
Re: Jill is dividing her ten-person class into two teams
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09 Jun 2019, 10:14
Expert Reply
We can divide a group of 10 people into 2 teams of 5 in \(\frac{C^5_{10}*C^5_5}{2!}=126\) ways (dividing by 2! because the order of the groups doesn't matter).
gmatclubot
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