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Jimmy stands at the window of an apartment which is 40 feet above the
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05 Mar 2024, 01:07
05 Mar 2024, 01:07
Expert Reply
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Question Stats:
72% (01:53) correct
27% (01:02) wrong based on 11 sessions
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Jimmy stands at the window of an apartment which is 40 feet above the ground. He releases a glider which flies a straight path to his friend, who catches the glider 10 feet above the ground in the neighboring building. If the buildings are 40 feet apart, what is the distance traveled by the glider?
A. \(10 \sqrt{17}\) feet
B. \(10 \sqrt{41}\) feet
C. \(40 \sqrt{2}\) feet
D. 50 feet
E. 70 feet
A. \(10 \sqrt{17}\) feet
B. \(10 \sqrt{41}\) feet
C. \(40 \sqrt{2}\) feet
D. 50 feet
E. 70 feet
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: Jimmy stands at the window of an apartment which is 40 feet above the
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07 Apr 2024, 02:03
07 Apr 2024, 02:03
Expert Reply
The given data lays out the dimensions of a right triangle. The clue you are given is that the start of the glider is 40 feet above the ground (distance to the ground is always measured along a line perpendicular to the ground). The glider starts its journey 40 feet above the ground and ends 10 feet above ground. Therefore, the height of the triangle is 30 feet. You are given the distance between the two buildings as 40 feet. You thus have the two legs of the triangle at 30 and 40. You should recognize this as a multiple of the Pythagorean Theorem proportions of 3:4:5 and so arrive at SO for the last side. The calculation is:
\(a^2+b^2=c^2\)
\(30^2+40^2=c^2\)
\(c^2=\sqrt{2500}\)
\(c=50\)
D is the answer
\(a^2+b^2=c^2\)
\(30^2+40^2=c^2\)
\(c^2=\sqrt{2500}\)
\(c=50\)
D is the answer
gmatclubot
Re: Jimmy stands at the window of an apartment which is 40 feet above the [#permalink]
07 Apr 2024, 02:03
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