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Let m and $n$ be real numbers such that m+1<n
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16 Jul 2026, 23:22
16 Jul 2026, 23:22
Expert Reply
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Question Stats:
68% (00:34) correct
32% (00:42) wrong based on 25 sessions
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Let \(m\) and \(n\) be real numbers such that \(m+1<n\) .
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(m\) |
\(n-1\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
- Part of the project: GRE Daily Quant Challenge ALL 4 CORE QUANT AREAS
- Also replying to the unanswered questions
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Joined: 20 Feb 2017
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Re: Let m and $n$ be real numbers such that m+1<n
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19 Jul 2026, 10:41
19 Jul 2026, 10:41
Expert Reply
Explanation
From the given condition: \(m+1<n\)
Subtract 1 from both sides: \(m<n−1\)
So:
Quantity \(A = m\)
Quantity \(B = n−1\)
Since \(m<n−1,\) Quantity B is always greater.
Answer: B.
From the given condition: \(m+1<n\)
Subtract 1 from both sides: \(m<n−1\)
So:
Quantity \(A = m\)
Quantity \(B = n−1\)
Since \(m<n−1,\) Quantity B is always greater.
Answer: B.
gmatclubot
Re: Let m and $n$ be real numbers such that m+1<n [#permalink]
19 Jul 2026, 10:41
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