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Let the operation
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30 Jun 2020, 09:02
30 Jun 2020, 09:02
Expert Reply
00:00
Question Stats:
91% (01:01) correct
8% (01:50) wrong based on 61 sessions
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Let the operation \(\blacklozenge\) and \(\blacksquare\) be defined fo all numbers r and s as
\(r\) \(\blacklozenge\) \(s\) \(= 6r+s\)
\(r\) \(\blacksquare\) \(s = 2r+s\)
If \(6x\) \(\blacklozenge\) \(8=34\) \(\blacksquare\) \(6x\), what is the value of x ?
\(r\) \(\blacklozenge\) \(s\) \(= 6r+s\)
\(r\) \(\blacksquare\) \(s = 2r+s\)
If \(6x\) \(\blacklozenge\) \(8=34\) \(\blacksquare\) \(6x\), what is the value of x ?
Show: :: OA
2
Re: Let the operation
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30 Jun 2020, 09:04
30 Jun 2020, 09:04
Expert Reply
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: Let the operation
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01 Jul 2020, 04:01
01 Jul 2020, 04:01
2
6x ⧫ 8 refers to r ⧫ s where r = 6x and s = 8 then:
6r + s = 6(6x) + 8 = 36x + 8
34 ◼ 6x refers to r ◼ s where r = 34 and s = 6x then:
2r + s = 2(34) + 6x = 68 + 6x
Finally:
36x + 8 = 68 + 6x
30x = 60
x = 2
6r + s = 6(6x) + 8 = 36x + 8
34 ◼ 6x refers to r ◼ s where r = 34 and s = 6x then:
2r + s = 2(34) + 6x = 68 + 6x
Finally:
36x + 8 = 68 + 6x
30x = 60
x = 2
