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Senior Manager

Joined: **23 Jan 2021 **

Posts: **294**

Given Kudos: **81 **

Concentration: **, International Business**

Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
28 Oct 2021, 21:27

Question Stats:

Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?

A.19

B. 20

C. 21

D. 22

E. 23

Post a detailed solution and get kudos!

A.19

B. 20

C. 21

D. 22

E. 23

Post a detailed solution and get kudos!

Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
29 Oct 2021, 22:54

1

Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?

Number of ways in which 1 jacket, 1 pant and 1 pair of shoes can be selected = 4*3*2 = 24

Number of ways of selecting 1 jacket and 1 pant which don`t match = 1*1*2 = 2

Required number of ways = (Total number of ways) - (Number of ways in which jacket and pant dont match)

= 24 - 2 = 22

D is correct

Senior Manager

Joined: **23 Jan 2021 **

Posts: **294**

Given Kudos: **81 **

Concentration: **, International Business**

Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
30 Oct 2021, 00:45

kapil1 wrote:

Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?

Number of ways in which 1 jacket, 1 pant and 1 pair of shoes can be selected = 4*3*2 = 24

Number of ways of selecting 1 jacket and 1 pant which don`t match = 1*1*2 = 2

Required number of ways = (Total number of ways) - (Number of ways in which jacket and pant dont match)

= 24 - 2 = 22

D is correct

I am confused in the highlighted line sir.

Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
30 Oct 2021, 23:16

COolguy101 wrote:

kapil1 wrote:

Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1 jacket, 1 pant and 1 pair of shoes every day. However, 1 jacket and 1 pant don`t match, so they cannot be selected together. In such circumstances, for how many days can she wear differently?

Number of ways in which 1 jacket, 1 pant and 1 pair of shoes can be selected = 4*3*2 = 24

Number of ways of selecting 1 jacket and 1 pant which don`t match = 1*1*2 = 2

Required number of ways = (Total number of ways) - (Number of ways in which jacket and pant dont match)

= 24 - 2 = 22

D is correct

I am confused in the highlighted line sir.

This is a case of selecting together 1 jacket and 1 pant which don`t match, and a pair of shoes.

Hence, 1*1*2 = 2 ways

Subtracting this case from the total number of cases = 24 - 2 =22

Senior Manager

Joined: **23 Jan 2021 **

Posts: **294**

Given Kudos: **81 **

Concentration: **, International Business**

Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
31 Oct 2021, 03:50

Sir, if prompt says two jacket and 2 pant wont match , then what will be the final answer kapil1 sir

Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
02 Nov 2021, 01:52

1

Shouldn't the answer be A, B, C, D ? because she can wear differently for 19, 20, 21, and 22 days. From the 23rd day onwards, she has to wear that forbidden pant-jacket combination. I think the wording of the question needs to be - what is the maximum possible number of days that she can wear differently , then answer D is correct.

Re: Linda has 4 jackets, 3 pants and 2 pairs of shoes. She could choose 1
[#permalink]
26 Nov 2023, 06:28

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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