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m+ \sqrt51
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06 Sep 2019, 05:53
06 Sep 2019, 05:53
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Question Stats:
85% (00:39) correct
14% (00:25) wrong based on 62 sessions
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\(m > 8\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(m + \sqrt{51}\) |
\(\sqrt{64} + 7\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: m+ \sqrt51
[#permalink]
08 Apr 2020, 04:50
08 Apr 2020, 04:50
1
Carcass wrote:
\(m > 8\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(m + \sqrt{51}\) |
\(\sqrt{64} + 7\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Here,
We know \(\sqrt{64} \)= 8 and \(\sqrt{49}\) = 7
therefore, \(\sqrt{51}\) should be in between 7 < \(\sqrt{51}\) < 8
QTY A = \(m + \sqrt{51}\)) = m + 7 = 8.1 + 7 = 15.1 ( since m >8 and considering the lowest possible values)
QTY B = \(\sqrt{64} + 7\) = 8 + 7 = 15
Hence, QTY A > QTY B
Re: m+ \sqrt51
[#permalink]
21 Jan 2023, 22:22
21 Jan 2023, 22:22
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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