Re: Machine P produces parts twice as fast as machine Q does. Machine Q pr
[#permalink]
04 Feb 2024, 02:52
The answers are A and E.
Rate of Machine Q = 100 parts of product K in n minutes = 100/n per minute
--> Rate of machine P = 200 parts of product K in n minutes = 200/n per minute
Now, rate = work / time
--> Rate of Machine Q = 100/(3/2) = 200/3 parts of product R in n minutes = 200/3n per minute
& Rate of Machine P = 200/(3/2) = 400/3 parts of product R in n minutes = 400/3n per minute
Therefore, in t minutes, Machine P will produce (400/3n) * t = 400t/3n
Also, if we divide both the numerator and the denominator by 400, we get option E.