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Marge has n candies, where n is an integer such that 20 < n < 50. If M
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24 Jan 2022, 06:04
24 Jan 2022, 06:04
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60% (01:17) correct
40% (01:34) wrong based on 5 sessions
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Marge has n candies, where n is an integer such that \(20 < n < 50\). If Marge divides the candies equally among 5 children, she will have 2 candies remaining. If she divides the candies among 6 children, she will have 1 candy remaining. How many candies will remain if she divides the candies among 7 children?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Marge has n candies, where n is an integer such that 20 < n < 50. If M
[#permalink]
24 Jan 2022, 20:00
24 Jan 2022, 20:00
\(n\) candies with \(20 < n < 50\)
If Marge divides the candies equally among \(5\) children, she will have \(2\) candies remaining.
so \(n = 5x + 2\) so candies can be \(22, 27, 32, 37, 42, 47\)
If she divides the candies among 6 children, she will have 1 candy remaining.
so \(n = 6y + 1\) so candies can be \(25, 31, 37, 43, 49\)
The common value among both is \(37\)
\(n = 37\)
If she divides among \(7\) children, each will get \(5\) candies with \(2\) candies remaining.
Answer C
If Marge divides the candies equally among \(5\) children, she will have \(2\) candies remaining.
so \(n = 5x + 2\) so candies can be \(22, 27, 32, 37, 42, 47\)
If she divides the candies among 6 children, she will have 1 candy remaining.
so \(n = 6y + 1\) so candies can be \(25, 31, 37, 43, 49\)
The common value among both is \(37\)
\(n = 37\)
If she divides among \(7\) children, each will get \(5\) candies with \(2\) candies remaining.
Answer C
gmatclubot
Marge has n candies, where n is an integer such that 20 < n < 50. If M [#permalink]
24 Jan 2022, 20:00
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